What are the Class C Subnetting questions which are asked in IT MNC'S interview today?

1. A small office network needs to be divided into four subnets with each subnet having a minimum of 10 host addresses. Design a subnetting scheme for the office network.

Solution:

To accommodate a minimum of 10 host addresses per subnet, we need a subnet size of 16 addresses (2^4 = 16). Borrowing 4 bits from the host portion will create 16 addresses per subnet.

Subnet 1:

Network Address: 192.168.0.0/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.1 - 192.168.0.14

Subnet 2:

Network Address: 192.168.0.16/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.17 - 192.168.0.30

Subnet 3:

Network Address: 192.168.0.32/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.33 - 192.168.0.46

Subnet 4:

Network Address: 192.168.0.48/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.49 - 192.168.0.62

2. A company has three departments: Sales, Marketing, and Finance. The Sales department requires 30 host addresses, Marketing requires 20 host addresses, and Finance requires 15 host addresses. Create a subnetting plan for the company.

Solution:

To accommodate the required number of host addresses for each department, we need subnet sizes as follows:

Sales:

Subnet Size: 32 addresses (2^5 = 32)

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.1 - 192.168.0.30

Marketing:

Subnet Size: 32 addresses (2^5 = 32)

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.33 - 192.168.0.62

Finance:

Subnet Size: 16 addresses (2^4 = 16)

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.65 - 192.168.0.78

3. A university has multiple campuses, and each campus needs a separate subnet with a minimum of 50 host addresses. Design a subnetting scheme for the university's network.

Solution:

To accommodate a minimum of 50 host addresses per campus, we need a subnet size of 64 addresses (2^6 = 64). Borrowing 6 bits from the host portion will create 64 addresses per subnet.

Campus 1:

Network Address: 192.168.0.0/26

Subnet Mask: 255.255.255.192

Usable Host Range: 192.168.0.1 - 192.168.0.62

Campus 2:

Network Address: 192.168.0.64/26

Subnet Mask: 255.255.255.192

Usable Host Range: 192.168.0.65 - 192.168.0.126

Campus 3:

Network Address: 192.168.0.128/26

Subnet Mask: 255.255.255.192

Usable Host Range: 192.168.0.129 - 192.168.0.190

4. A retail store chain has 12 locations, and each location requires a subnet with a minimum of 25 host addresses. Develop a subnetting plan for the store chain.

Solution:

To accommodate a minimum of 25 host addresses per location, we need a subnet size of 32 addresses (2^5 = 32). Borrowing 5 bits from the host portion will create 32 addresses per subnet.

Location 1:

Network Address: 192.168.0.0/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.1 - 192.168.0.30

Location 2:

Network Address: 192.168.0.32/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.33 - 192.168.0.62

Location 3:

Network Address: 192.168.0.64/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.65 - 192.168.0.94

Location 4:

Network Address: 192.168.0.96/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.97 - 192.168.0.126

Location 5:

Network Address: 192.168.0.128/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.129 - 192.168.0.158

Location 6:

Network Address: 192.168.0.160/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.161 - 192.168.0.190

Location 7:

Network Address: 192.168.0.192/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.193 - 192.168.0.222

Location 8:

Network Address: 192.168.0.224/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.225 - 192.168.0.254

Location 9:

Network Address: 192.168.1.0/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.1.1 - 192.168.1.30

Location 10:

Network Address: 192.168.1.32/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.1.33 - 192.168.1.62

Location 11:

Network Address: 192.168.1.64/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.1.65 - 192.168.1.94

Location 12:

Network Address: 192.168.1.96/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.1.97 - 192.168.1.126

5. A hotel has four floors, and each floor needs a separate subnet with a minimum of 20 host addresses. Design a subnetting scheme for the hotel's network.

Solution:

To accommodate a minimum of 20 host addresses per floor, we need a subnet size of 32 addresses (2^5 = 32). Borrowing 5 bits from the host portion will create 32 addresses per subnet.

Floor 1:

Network Address: 192.168.0.0/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.1 - 192.168.0.30


Floor 2:

Network Address: 192.168.0.32/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.33 - 192.168.0.62


Floor 3:

Network Address: 192.168.0.64/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.65 - 192.168.0.94


Floor 4:

Network Address: 192.168.0.96/27

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.97 - 192.168.0.126

6. An internet service provider (ISP) wants to allocate subnets to its residential customers. Each customer should have a subnet with a minimum of 5 host addresses. Develop a subnetting plan for the ISP.

Solution:

To accommodate a minimum of 5 host addresses per customer, we need a subnet size of 8 addresses (2^3 = 8). Borrowing 3 bits from the host portion will create 8 addresses per subnet.

Customer 1:

Network Address: 192.168.0.0/29

Subnet Mask: 255.255.255.248

Usable Host Range: 192.168.0.1 - 192.168.0.6


Customer 2:

Network Address: 192.168.0.8/29

Subnet Mask: 255.255.255.248

Usable Host Range: 192.168.0.9 - 192.168.0.14


Customer 3:

Network Address: 192.168.0.16/29

Subnet Mask: 255.255.255.248

Usable Host Range: 192.168.0.17 - 192.168.0.22


Customer 4:

Network Address: 192.168.0.24/29

Subnet Mask: 255.255.255.248

Usable Host Range: 192.168.0.25 - 192.168.0.30

7. A manufacturing company has multiple production lines, and each production line requires a subnet with a minimum of 15 host addresses. Create a subnetting scheme for the company's network.

Solution:

To accommodate a minimum of 15 host addresses per production line, we need a subnet size of 16 addresses (2^4 = 16). Borrowing 4 bits from the host portion will create 16 addresses per subnet.

Production Line 1:

Network Address: 192.168.0.0/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.1 - 192.168.0.14


Production Line 2:

Network Address: 192.168.0.16/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.17 - 192.168.0.30


Production Line 3:

Network Address: 192.168.0.32/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.33 - 192.168.0.46


Production Line 4:

Network Address: 192.168.0.48/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.49 - 192.168.0.62

8. A call center has three departments: Customer Support, Sales, and Technical Support. The Customer Support department requires 50 host addresses, Sales requires 30 host addresses, and Technical Support requires 25 host addresses. Design a subnetting plan for the call center.

Solution:

To accommodate the required number of host addresses for each department, we need subnet sizes as follows:

Customer Support:

Subnet Size: 64 addresses (2^6 = 64)

Subnet Mask: 255.255.255.192

Usable Host Range: 192.168.0.1 - 192.168.0.62


Sales:

Subnet Size: 32 addresses (2^5 = 32)

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.65 - 192.168.0.94


Technical Support:

Subnet Size: 32 addresses (2^5 = 32)

Subnet Mask: 255.255.255.224

Usable Host Range: 192.168.0.97 - 192.168.0.126

9. A school has six classrooms, and each classroom needs a separate subnet with a minimum of 10 host addresses. Develop a subnetting scheme for the school's network.

Solution:

To accommodate a minimum of 10 host addresses per classroom, we need a subnet size of 16 addresses (2^4 = 16). Borrowing 4 bits from the host portion will create 16 addresses per subnet.

Classroom 1:

Network Address: 192.168.0.0/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.1 - 192.168.0.14


Classroom 2:

Network Address: 192.168.0.16/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.17 - 192.168.0.30


Classroom 3:

Network Address: 192.168.0.32/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.33 - 192.168.0.46


Classroom 4:

Network Address: 192.168.0.48/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.49 - 192.168.0.62


Classroom 5:

Network Address: 192.168.0.64/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.65 - 192.168.0.78


Classroom 6:

Network Address: 192.168.0.80/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.81 - 192.168.0.94

10. A software development company has multiple development teams, and each team needs a subnet with a minimum of 8 host addresses. Create a subnetting scheme for the company's network.

Solution:

To accommodate a minimum of 8 host addresses per development team, we need a subnet size of 16 addresses (2^4 = 16). Borrowing 4 bits from the host portion will create 16 addresses per subnet.

Development Team 1:

Network Address: 192.168.0.0/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.1 - 192.168.0.14


Development Team 2:

Network Address: 192.168.0.16/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.17 - 192.168.0.30


Development Team 3:

Network Address: 192.168.0.32/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.33 - 192.168.0.46


Development Team 4:

Network Address: 192.168.0.48/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.49 - 192.168.0.62


Development Team 5:

Network Address: 192.168.0.64/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.65 - 192.168.0.78


Development Team 6:

Network Address: 192.168.0.80/28

Subnet Mask: 255.255.255.240

Usable Host Range: 192.168.0.81 - 192.168.0.94

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